def isclose(a, b, lim): # is b close to a OR to aliquot of a in lim if a == 0: return abs(b - a) <= lim else: n = b/a if b%a > a/2: n += 1 c = a*n # closest aliquot to b m = abs(b - c) return m <= lim...returns boolean.
It's usable to test dispersion of sample around peaks.
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Thanks for your posting!